Sorry to take ages to reply

JeevesBond — Wed, 10 Mar 2010 04:29:00 +0000

Sorry to take ages to reply to this, also welcome to TWF!

You've already partially got the answer in your code there, if you run:

var tableInputs = $("input[name='table[]']");

Then you'll be able to use tableInputs as an array:

alert(tableInputs[0]);

You don't even have to use an intermediate variable, this works just as well:

$("input[name='table[]']")[0];

Although, if you're going to use the array in a for loop it would be better to put the result of $("input[name='table[]']") into a variable, then the $ function won't be called on every iteration of the loop.