There is an issue with the

Greg K — Sun, 20 Jan 2013 16:28:39 +0000

There is an issue with the quotes being escaped.

<?php
foreach ($xml->entry as $entry)
{
    echo $entry->link[2]['href'] . "\n";  // output a new line
}
?>

I am kind of a novice at php

stephanie schultz — Tue, 23 Oct 2012 13:50:53 +0000

I am kind of a novice at php but there is an error in your last section of code and I don't know how to fix it.

pr0gr4mm3r — Tue, 06 Nov 2007 18:11:54 +0000

Like this?

First, load the feed and create the SimpleXML object.

<?php
$xmlstr = file_get_contents('http://api.flickr.com/services/feeds/photos_public.gne?tags=Ligabue');
$xml = new SimpleXMLElement($xmlstr);
?>

Then, figure out where the content is that you want. This means manually sorting through the XML tree (can be annoying) to find the path to the data you want. In your case, the links can be found at $xml->entry[]->link[2]['href']. Since there are multiple entries, we can loop through them like this:

<?php
foreach ($xml->entry as $entry)
?>

Now, inside the loop, you will start at the 'entry' element instead of the root XML element, so to access the link text, use $entry->link[2]['href']. More then one link is provided per entry. The one to the actual photo is the second one. To just output the links from inside the loop to produce the result on this page, use this:

<?php
foreach ($xml->entry as $entry)
{
    echo $entry->link[2]['href'] . \"\n\";
}
?>

Put the first and third code snippet together to create the linked result given at the top of the post. Hope this helps.