Neutron2k — Tue, 13 Dec 2005 15:21:50 +0000

you will need to loop through the result set after executing the regexp.

codehungry — Tue, 13 Dec 2005 13:41:04 +0000

Thanks CptAwesome!

This is what I was looking for...

Thanks again,
Andrew Schools

CptAwesome — Sun, 11 Dec 2005 09:41:10 +0000

actuallt one small change to that and an example

<?
$message = "
<a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a>
<a target=\"_blank\" href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a>
<a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif' target=\"_blank\">image</a>
<a href=\"http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif\" target=\"_blank\">image</a>
";



$regex = "(<a)?([A-z0-9 -=\"\'])+(href=)+(\'|\")+([A-z0-9\:\/\-_\.]{1,255})+(\.gif)+(\'|\")?([A-z0-9 -=\"\'])+>+[[:alnum:][:punct:]]+</a>";
$message = ereg_replace($regex,"<img src=\"\\5\\6\"><br />\n",$message);
echo $message;
?>

returns:
<img src="http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif"><br />

<img src="http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif"><br />

<img src="http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif"><br />

<img src="http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif"><br />

CptAwesome — Sun, 11 Dec 2005 09:37:02 +0000

$message = "<a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a> <a 

href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a>"; 
$regex = "(<a)?([A-z0-9 -=\"\'])+(href=)+(\'|\")+([A-z0-9\:\/\-_\.]{1,255})+(\.gif)+(\'|\")+>+[[:alnum:][:punct:]]+</a>";
$message = ereg_replace($regex,"<img src=\"\\5\\6\"><br />\n\n",$message);
echo $message;

codehungry — Sat, 10 Dec 2005 04:41:17 +0000

Quote:
A proublem with your Regual Expression string...
add "http://www." to the first section.

I've been using

(http://|https://|www.|ftp://)+

that will match everything I need. Looking at the previous code, I must have changed it in my attempt to fix the problem. Here's the new code:

<?php
$message = \"<a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a> <a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a>\";

$message = ereg_replace(\"(<a href='((http://|https://|www.|ftp://)+([[:alnum:]]|[[:punct:]])+\.gif)'>([[:alnum:]]|[[:punct:]]|[[:blank:]])+</a>)\",\"<img target=\\"_blank\\" src=\\"\\2\\">\", $message);
?>

Thanks,
Andrew Schools

codehungry — Sat, 10 Dec 2005 00:23:18 +0000

Hi, I get the following output:

<img target="_blank" src="http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif">

Thanks,
Andrew Schools

bja888 — Fri, 09 Dec 2005 23:35:48 +0000

Well, ill give you 2 choices.
1) wait for someone who knows php to answer the thread. (Eveyone else but me)
2) Show me the output of the string you parced and hope I can come up with the answer.

codehungry — Fri, 09 Dec 2005 23:27:16 +0000

Hi,

I did only run the ereg_replace() function once, however, it’s supposed to find every occurrence and replace it. For example, if I run the following script:

<?php
$message = \"I went to the store and got a gallon of milk and a loaf of bread.\";
$message = ereg_replace(\"(a[[:alpha:]]d)\",\"---\", $message);
?>

My output is the following:

I went to the store --- got a gallon of milk --- a loaf of bread.

Thanks,
Andrew Schools

bja888 — Fri, 09 Dec 2005 23:08:24 +0000

I am not familior with php but Regular expressions have been something I have used in other languages. It might be that you only ran the ereg_replace() only onece.

A proublem with your Regual Expression string...
add "http://www." to the first section.

codehungry — Fri, 09 Dec 2005 22:53:44 +0000

Hi bja888,

This is the string I'm parsing:

<?php
$message = \"<a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a> <a href='http://us.i1.yimg.com/us.yimg.com/i/us/my/addtomyyahoo4.gif'>image</a>\";
?>

Thanks,
Andrew Schools