airoid3000 — Sat, 27 Mar 2004 22:12:14 +0000

It should be:

mjs416 — Fri, 26 Mar 2004 18:22:05 +0000

Since I am a php newbie, this looked like a good example to play with and try to figure some things out. What keeps happening, however, is that I get the "Please specify a valid ID." Here is what I have:

--------------------------------------

<?php
// config.php 
$products = array( 

// #0 
array('title' => 'Arrangement One', 
    'price' => '$13.49', 
    'image' => 'images/1.gif'), 


// #1 
array('title' => 'Arrangement Two', 
    'price' => '$15.89', 
    'image' => 'images/2.gif'), 
    
array('title' => 'Arrangement Three', 
    'price' => '$17.89', 
    'image' => 'images/3.gif'), 

); 
?>

-------------------------------------------

now the script that I call "cart.php"

------------------------------------------

<?php
 
// page to load with your popup. pass the number with the url. ex: thisscript.php?id=0 

include('config.php'); 

if(!isset($_GET['id']) || !isset($products[$_GET['id']])) 
    die('Please specify a valid ID.'); 

$p = $products[$_GET['id']]; 

?>

" border="0" />
<?=$p['price']?>

---------------------------------------------------

I then have a php page called index that has three links:

1
2
3

But, as mentioned, the code cannot determine a valid ID. Any idea what I am doing wrong? I'm sure I am way off base here. I have a few books on php coming in the mail to aid me, but for right now, any ideas?

Edit: NM, Fixed it myself. This reminds me of the good ol days of troubleshooting my old C code in college. Yikes!!! Anyways, thanks for the input guys.

Chroder — Fri, 26 Mar 2004 04:33:47 +0000

You want to go through each config value and print it on one page? Thats simple enough

<?php
include('database.php');

foreach($products AS $p)
{

<b>=$p['title']</b>: =$p['price']<br />

}
?>

Suzanne — Fri, 26 Mar 2004 03:41:46 +0000

moving it to scripting.

airoid3000 — Fri, 26 Mar 2004 01:58:56 +0000

I have tried several different ways, but none worked. Here is what I am looking for exactly:

<?php
 
// page to load with your popup. pass the number with the url. ex: thisscript.php?id=0 

include('database.php'); 

if(!isset($_GET['id']) || !isset($products[$_GET['id']])) 
die('We apologize, but this occasion category is currently unavailable.'); 

$p = $products[$_GET['id']]; 

<html>        
Arrangement Title: =$products['id'] => '1001'['title']
</html> 
?>

airoid3000 — Fri, 26 Mar 2004 01:11:59 +0000

I have a page that displays all of the flower arrangements and their prices. Is there a way that I can call the prices and names from my config.php file?

Changing prices is very hard because now I have to change them in the config.php file, and the flower arrangement page.

Chroder — Mon, 08 Mar 2004 03:12:05 +0000

Quote: Ah, it was an error in my part, seems to be working fine now. My problem wasn't about having javascript in php, because the javascript was actually after ?> (the close of php) on the page.

I'll have to run that by my buddy there

Quote: Thanks for everything! You're a life saver!

No problem

airoid3000 — Mon, 08 Mar 2004 03:04:28 +0000

Ah, it was an error in my part, seems to be working fine now. My problem wasn't about having javascript in php, because the javascript was actually after ?> (the close of php) on the page.

Thanks for everything! You're a life saver!

Chroder — Mon, 08 Mar 2004 02:49:17 +0000

Thats weird that you say that, I had a discussion about the very same thing on my forum -- never got to the bottom of it. I though I was missing something. I'll search for an answer later -- gotta do homework now

airoid3000 — Mon, 08 Mar 2004 02:43:23 +0000

Your awesome! I have everything working but one thing, the buy now button. It calls a javascript file in order to add the specific product to the cart.

Everytime I click buy now i get an "object expected" error. Is this because .php pages don't allow javascript in them, or what?

Thanks again!