mairving — Mon, 11 Mar 2002 13:16:33 +0000

Question about this statement:
if (($finalPrice - 2) > $paymentInterval) {
$finalPrice = $finalPrice - $paymentInterval;

Here is what is said, if finalprice -2 less than paymentinterval
then finalprice = finalprice - paymentinterval. Okay but where does the paymentinterval value come from?

Mark Hensler — Mon, 11 Mar 2002 05:17:53 +0000

I can't duplicate any errors. What values do I need to provide to get an error?

shanda — Mon, 11 Mar 2002 02:19:09 +0000

$intV = array(1,12,24);
$percent = 10;
$unitBW = 1;

if ($valHD <= 0) $valHD = 50;

if ($valHD < 100) $perHD = 0.055;
elseif ($valHD <=300) $perHD = 0.0499;
elseif ($valHD <= 400) $perHD = 0.047475;
elseif ($valHD <= 500) $perHD = 0.04598;
elseif ($valHD <= 600) $perHD = 0.04665;
else $perHD = 0.035;

$valBW = $valBW / $unitBW;

$finalPrice =(($percent + 100)/100) *($valHD * $perHD);

if (($finalPrice - 2) > $paymentInterval) {
$finalPrice = $finalPrice - $paymentInterval;
}

$finalPrice = number_format($finalPrice, 2);
$payFirst = number_format(($finalPrice * $intV[$paymentInterval]), 2);

}

Mark Hensler — Sun, 10 Mar 2002 20:12:31 +0000

1082 is such an odd number. Can we see any code associated with the problem?

mairving — Sun, 10 Mar 2002 17:09:48 +0000

I am assuming that this is being dumped into a database. If so, the first thing I always do is make sure that the SQL itself works. Take your insert statement from PHP and if this fails in MySQL, it will help you identify the problem.

In looking at your form, you should probably put a maximum size on the form field.

Posting your script here using the php tags would help us determine the problem.