did you try it / read the docs

japhy — Sat, 21 Oct 2000 11:22:45 +0000

No, trust me. require does not take a list of files. perldoc -f require

Mark Hensler — Sat, 21 Oct 2000 04:35:29 +0000

How 'bout this:

require "text1.txt","text2.txt";

like:
print "this","and","this";

did you try it?

japhy — Sat, 21 Oct 2000 04:03:46 +0000

No, Suzanne, I'm afraid you can't. require() takes at most one argument, and that argument MUST be the name of a module, or the path to a single file to be included. To include several files at once, make an array of them, and require each element of the array separately:

# pre-5.005 code
for (@files) { require }
 
# 5.005 and later
require for @files;

It's just require "";

Suzanne — Sat, 21 Oct 2000 04:00:04 +0000

require "file.txt";
require "file2.txt";
require "files.txt";

Most scripts and programmers recommend you have it near the top of the script/program, before the variables, for ease.

Suzanne

P.S. This was edited to correct my brain fart, thank you!

[Edited by Suzanne on 10-21-2000 at 03:23 AM]

fairhousing — Sat, 21 Oct 2000 02:26:52 +0000

yeah, require will probably do it for u.

japhy — Fri, 20 Oct 2000 15:51:13 +0000

You probably want the require() function, or perhaps the do() function. Be warned, files included into your program should end with the line

1;

because Perl expects them to return a true value (that indicates success).