gokhan — Fri, 15 Sep 2000 07:29:43 +0000

you should start reading abour perl a little, because die/warn is one of debugging tools. Do you know what is strict?

Mark Hensler — Thu, 14 Sep 2000 23:49:47 +0000

if (!$this)
die("\$this doesn't exist");

this will evaluate (see if $this doesn't exist). If $this doesn't exist, it returns true, and executes the next statement (the next line here).

The die() functoin simply prints the ("string") and kills (stops) the script.

Nightspirit — Thu, 14 Sep 2000 12:42:22 +0000

hey man.

yeah i guess it was bad programming on my part. im still trying to grasp most of the basics of PHP and mySQL.

thanks anyway.

-= Edit =-

Urr...what the hell is a DIE statement?

[Edited by Nightspirit on 09-14-2000 at 08:46 AM]

Mark Hensler — Wed, 13 Sep 2000 06:08:00 +0000

post the code...
Then I can decifer it.

my guess is that you are using $result wrong (duh, huh?)

You need to use it like:

$query = "SELECT * FROM tablename";

$result = mysql_query ($query);
if (!$result)
	die ("Query Error");

while ($MyStuff = mysql_fetch_array ($result)) {
print $MyStuff["fieldname"];
}

There are several different ways to print data from the $result. This is just one of them (probably not the one you need either). Anyway, if you can, post the code.