I'd like to create a conditional include that will display content only if the include file is present.
Here's my include as it is scripted now:
<?php
// import file
include("wp-content/plugins/stuff.inc");
?> How would I add a conditional statement that would display nothing if stuff.inc is not present?
Thanks
kazimmerman posted this at 13:14 — 21st June 2009.
He has: 670 posts
Joined: Jul 2005
Something like this:
<?php$file = "wp-content/plugins/stuff.inc"
if (file_exists($file)) {
include($file);
}
?>
greg posted this at 14:16 — 21st June 2009.
He has: 1,580 posts
Joined: Nov 2005
Or if you don't want anything "at all" to happen if the file is not included and stop the entire page load and rest of script, use this:
<?phpif (!include('wp-content/plugins/stuff.inc')){
exit('file not available');
}
?>
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teammatt3 posted this at 19:02 — 21st June 2009.
He has: 2,076 posts
Joined: Sep 2003
Isn't that the definition of require? It stops execution of the script if the file isn't available.
<?php@include 'wp-content/plugins/stuff.inc';
?>
might achieve the desired result. The @ symbol will suppress the warning that is produced if the file is not available.
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greg posted this at 19:20 — 21st June 2009.
He has: 1,580 posts
Joined: Nov 2005
Include() only issues an E_WARNING, allowing a message and rest of page, or as my example with an exit.
Ideally you would include the header/content/footer/navigation etc with a message then exit() if desired, or "other" criteria if the file was not available.
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